Nuprl Lemma : es-interface-restrict-disjoint 11,40

A:Type, es:ES, I:AbsInterface(A), P:(E), p:(e:E. Dec(P(e))). (I|p (I|p) = 0 
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DefinitionsFalse, P  Q, A, x:AB(x), x(s), P & Q, b, f(a), x:A  B(x), x:AB(x), P  Q, xt(x), P  Q, Void, E, Dec(P), Type, , AbsInterface(A), ES, X  Y = 0
Lemmases-is-interface-restrict, not functionality wrt iff, and functionality wrt iff, es-is-interface-co-restrict

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